Determine the miles of pipe

9000 ft

= 1.70 mi

5,280 ft/mi

Determine head loss

Hf = 28.8 ft/mi x 1.70 mi = 49 ft

Determine head remaining

225 ft - 49 ft = 176 ft

fittings result from the same surface friction losses in straight pipe. So

far we have only considered the losses in pipe. Now we are going to find

out how to compute the losses through valves and fittings. Valves and

fittings have been mathematically evaluated to determine the friction loss

and the information has been put in graph form. Special consideration must

be given to terminals and tank farms because of the numbers of valves and

fitting used. This friction loss must be carefully evaluated to ensure that

feeder pumps can meet the required pressure to feed the mainline pumps and

to transfer fuel from tank to tank within the terminal.

Now we can calculate the equivalent length for a pipeline that has a

certain number of valves and fittings. This number would then be added to

the pipeline length. For example:

3 rising stem gate valves

2 swing check valves

1 90 degree welding elbow

All valves and fittings are 8.415 inch diameter

Gate valve - 6.2 x 3 = 18.6

Swing check valve - 70.0 x 2 = 140

90 degree welding elbow 95.0 x 1 = 9.5

Total

= 168 ft

Given:

JP-5 at 80, F

Q = 700 GPM

d = 8.415 inches

Valves and fitting equivalent length = 188 Feet

Pipe length = 2.5 mi

Find:

Total head loss due to friction (Hf)

Determine Hg

NOTE:

Using Figure 2-1, at 700 GPM and 8.415 inch pipe Hg = 34 ft/mi

Determine correction factor using Table 2-1.

Correction factor = 1.17

Determine True Gradient

12-24

QM 5099

Integrated Publishing, Inc. |