PROBLEM: Determine the feet of head:

SOLUTION:

PSI

SG

HL

25

.7250

79.7

50

.8420

137.2

100

.8035

287.5

PROBLEM: Determine pressure in PSI:

SOLUTION:

HL

SG

PSI

100

.7040

30.5

250

.7777

84.2

500

.8250

178.6

(c) Velocity of Flow: It is the flow speed usually measured in feet per second, equal to

flow rate (Q) in cubic feet per second, divided by the cross sectional area (A) of the pipe in square feet.

A = 0.785 x D2

V=Q/A

D = Inside diameter in feet

PROBLEM: Determine the flow velocity in ft/sec:

Data: Q = 1,000 barrels per hour

D = 6 inches

SOLUTION:

Q = 1000BBL x 42 Gal x 1 ft3 x 1 Hr x 1 Min =1.56 ft3

Hr

1 BBL 7.48 Gal 60 Min 60 Sec

Sec

D = 6 in x l ft =.5ft

12in

A = .785 x .52 = .785 x .25 = .2 ft2

V = 1.56 = 7.8 ft/sec

.2

(d) Flow Type: There are three types of flow Laminar, transitional, and turbulent. To

find out the flow type in a military pipeline we use the Reynold's number (Re) formulas.

(1)

Re formula using field data formula:

Re = 3160 x Q Where Q = Flow rate, GPM

dxK

d = Pipe inside diameter, inches

K = Viscosity, centistokes, cSt

(2)

Re formula using design data:

Re = VD/Y

Where V = Velocity, ft/sec

D = Pipe inside diameter, feet

Y = Viscosity, ft2/sec

QM5203

1-19

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