PROBLEM: Determine the feet of head:
SOLUTION:
PSI
SG
HL
25
.7250
79.7
50
.8420
137.2
100
.8035
287.5
PROBLEM: Determine pressure in PSI:
SOLUTION:
HL
SG
PSI
100
.7040
30.5
250
.7777
84.2
500
.8250
178.6
(c) Velocity of Flow: It is the flow speed usually measured in feet per second, equal to
flow rate (Q) in cubic feet per second, divided by the cross sectional area (A) of the pipe in square feet.
A = 0.785 x D2
V=Q/A
D = Inside diameter in feet
PROBLEM: Determine the flow velocity in ft/sec:
Data: Q = 1,000 barrels per hour
D = 6 inches
SOLUTION:
Q = 1000BBL x 42 Gal x 1 ft3 x 1 Hr x 1 Min =1.56 ft3
Hr
1 BBL 7.48 Gal 60 Min 60 Sec
Sec
D = 6 in x l ft =.5ft
12in
A = .785 x .52 = .785 x .25 = .2 ft2
V = 1.56 = 7.8 ft/sec
.2
(d) Flow Type: There are three types of flow Laminar, transitional, and turbulent. To
find out the flow type in a military pipeline we use the Reynold's number (Re) formulas.
(1)
Re formula using field data formula:
Re = 3160 x Q Where Q = Flow rate, GPM
dxK
d = Pipe inside diameter, inches
K = Viscosity, centistokes, cSt
(2)
Re formula using design data:
Re = VD/Y
Where V = Velocity, ft/sec
D = Pipe inside diameter, feet
Y = Viscosity, ft2/sec
QM5203
1-19
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