A = length of side X length of side = length of side (same as a rectangle, but all sides are equal)
Diameter - straight line passing through center of circle and stopping at the circumference.
Circumference ,, Pi or 2 x radius.
Radius - line from center of circle to its circumference.
Circumference - perimeter of a circle. Pi x diameter.
Pi = Circumference ,, Diameter or 3.14159. Pi is a constant, it never changes.
Area = Pi x Radius
PART H - VOLUME
Volume is how much something will hold. Area will not hold anything, only cover it. Volume is expressed in
cubic units. All measurements must be in the same units before you begin using any of the formulas listed
Volume of a box= Length x Width x Height.
Volume of a cube= Side x Side x Side= Side . (same as a box, but all sides are equal)
Volume of a Cylinder= area of the base x height. Since the base of cylinders are round, we will need to
use the formula for the area of a circle - Pi x R x H.
Conversion: cubic feet to gallons - 1 cubic ft = 7.48 gal. Gallons to barrels - 1 bbl = 42 gal.
PART I - CALCULATING FOR AN UNKNOWN
IN FIRST DEGREE EQUATIONS
The last objective we want to cover is to calculate the unknown value in the equations by calculating velocity of flow
in a pipeline when given the other two values in the formula.
An equation is no more than a statement that says "what's on the right side is the same as what's on the left side."
Q = the volumetric flow rate, measured in cubic ft/sec
V = the velocity of flow, measured in ft/sec
A = the cross sectioned area of the pipe, measured in square feet.
Q = VA
and V = Q
If A = .2245 ft and Q = 1.2246 cubic ft/sec, what is the velocity of flow in ft/sec?
We have both Q and A and must solve for V as follows:
V = 1.2246 cubic ft/sec
.2245 sq ft.
V = 5.45 ft/sec (round off to the 100th)
We can then anticipate product moving through the pipeline at a speed of 5.45 ft/sec.