1 cubic foot over 7.48 gallons, you can cancel out the gallons measurements in the numerator and

denominator, and you are left with 1 cubic foot over minutes multiplied by times 7.48.

(e) For the minutes to seconds conversion, simply multiply the fraction by 1 minute over 60

seconds. This will cancel out the minutes in the equation. You now are left with a unit of measurement

of cubic feet over seconds, just what you were supposed to convert to. The rest is just a math problem.

Along with the factors, you have 1 multiplied by 1 in the numerator and 7.48 multiplied by 60 in the

denominator.

That equals 1 over 448.8 or 0.002228, which is the conversion factor found in FM 10-67-1. Figure 1-1

illustrates how to accomplish this action.

c. Velocity. Velocity, like flow rate, uses one unit of measurement over another. While flow rate

measures volume of liquid over time, velocity measures distance traveled over time. More simply

stated, it is a measure of speed. The common abbreviation for velocity is "V."

(1) Distance is commonly measured in miles, feet, and inches. However, it can also be

measured in metric measurements. Since the denominator in velocities (hours, seconds, etc.) is the same

as for flow rates, common velocities we use in the petroleum field are: miles per hour and feet per

second.

(2) Since there are no conversion factors for velocity listed in FM 10-67-1, we must convert all

velocities by hand using the same process we used to convert flow rates.

(a) In this instance, the required conversion is from miles per hour to feet per second. As

with the conversion for flow rates, both numerators are in the same type of measurement (distance) and

both denominators are measured in time.

(b) To convert from miles to feet, multiply by 5,280 feet over 1 mile. This allows

elimination of the miles and leaves you with 5,280 multiplied by feet over hour multiplied by one.

(c) Converting from hours to seconds can be done one of two ways: first, if you know

that 1 hour equals 3,600 seconds, then you can multiply by 1 hour over 3,600 seconds to eliminate hours

from the equation. In this example, we use the second method, first breaking hours down into 60

minutes and then breaking minutes down into 60 seconds.

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